Missing Number
Given an array `nums` containing n distinct numbers in the range [0, n], return the one number in that range that is missing from the array.
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Problem
Given an array nums containing n distinct numbers in the range [0, n], return the only number in the range that is missing from the array.
Input
An array `nums` of n distinct integers, each in the range [0, n].
Output
The one integer in [0, n] that is not present in `nums`.
Examples
Input: nums = [3,0,1]
Output: 2
n=3. Range is [0,1,2,3]. 2 is missing.
Input: nums = [0,1]
Output: 2
n=2. Range is [0,1,2]. 2 is missing.
Input: nums = [9,6,4,2,3,5,7,0,1]
Output: 8
n=9. 8 is the missing number.
The brute-force approach
For each number from 0 to n, check if it exists in nums using a linear scan or a Set.
seen = set(nums)
for i in range(len(nums) + 1):
if i not in seen:
return iBuilding the set is O(n). The scan is O(n). Total O(n) time and O(n) space. This is acceptable, but there are O(n) time O(1) space solutions.
Spotting the pattern
This is a Bit Manipulation problem. The key question to ask yourself:
If you add up all numbers that should be there and subtract all numbers that are there, what's left?
Answering that is where it clicks, and it's exactly what the guided walkthrough below builds with you: the pattern reasoning, a progressive hint ladder that never spoils the answer, a row-by-row dry run, the optimized solution, and an in-browser editor to run your code against real test cases.
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