Longest Increasing Subsequence
Given an integer array, return the length of the longest strictly increasing subsequence. A subsequence does not need to be contiguous.
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Problem
Given an integer array nums, return the length of the longest strictly increasing subsequence.
Input
An integer array `nums`.
Output
The length of the longest strictly increasing subsequence.
Examples
Input: nums = [10,9,2,5,3,7,101,18]
Output: 4
[2,3,7,101] or [2,5,7,101] are the longest, both length 4.
Input: nums = [0,1,0,3,2,3]
Output: 4
The brute-force approach
Generate all subsequences and find the longest one that is strictly increasing.
best = 0
for mask in range(1 << n):
subseq = [nums[i] for i in range(n) if mask & (1 << i)]
if all(subseq[i] < subseq[i+1] for i in range(len(subseq)-1)):
best = max(best, len(subseq))
return bestO(2^n × n) — trying all subsets.
Spotting the pattern
This is a Dynamic Programming problem. The key question to ask yourself:
If you know the longest increasing subsequence ending at each index before i, how do you compute the longest one ending at index i?
Answering that is where it clicks, and it's exactly what the guided walkthrough below builds with you: the pattern reasoning, a progressive hint ladder that never spoils the answer, a row-by-row dry run, the optimized solution, and an in-browser editor to run your code against real test cases.
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