Find Pivot Index
Given an integer array, return the leftmost pivot index where the sum of all elements to the left equals the sum of all elements to the right. Return -1 if no such index exists.
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Problem
Given an array of integers nums, calculate the pivot index of this array. The pivot index is the index where the sum of all the numbers strictly to the left of the index is equal to the sum of all the numbers strictly to the right of the index. Return the leftmost pivot index. If no such index exists, return -1.
Input
An integer array `nums`.
Output
The leftmost pivot index, or `-1` if none exists.
Examples
Input: nums = [1,7,3,6,5,6]
Output: 3
Left sum of index 3: 1+7+3=11. Right sum: 5+6=11.
Input: nums = [1,2,3]
Output: -1
Input: nums = [2,1,-1]
Output: 0
Index 0: left sum=0, right sum=1+(-1)=0.
The brute-force approach
For each index i, compute the sum of elements to the left and right separately. Return i if they match.
for i in range(n):
left = sum(nums[:i])
right = sum(nums[i+1:])
if left == right: return i
return -1O(n²) — recomputing left and right sums from scratch at each index.
Spotting the pattern
This is a Prefix Sum problem. The key question to ask yourself:
If you know the total sum and the running left sum, what formula gives you the right sum without scanning the array again?
Answering that is where it clicks, and it's exactly what the guided walkthrough below builds with you: the pattern reasoning, a progressive hint ladder that never spoils the answer, a row-by-row dry run, the optimized solution, and an in-browser editor to run your code against real test cases.
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