Combinations
Given two integers `n` and `k`, return all possible combinations of `k` numbers chosen from the range [1, n].
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Problem
Given two integers n and k, return all possible combinations of k numbers chosen from the range [1, n].
Input
Two integers `n` (the range [1,n]) and `k` (combination size).
Output
All possible combinations of k numbers from 1 to n. Order of combinations doesn't matter; order within each combination doesn't matter.
Examples
Input: n = 4, k = 2
Output: [[1,2],[1,3],[1,4],[2,3],[2,4],[3,4]]
All pairs from [1,2,3,4]. Order within each pair and order of pairs doesn't matter.
Input: n = 1, k = 1
Output: [[1]]
Only one choice.
The brute-force approach
Generate all possible subsets of size k using nested loops. This only works for fixed k — you'd need k nested loops.
# For k=2 specifically:
for i in range(1, n+1):
for j in range(i+1, n+1):
result.append([i, j])Requires k nested loops — only works for a fixed known k. Backtracking handles any k with a single recursive function.
Spotting the pattern
This is a Backtracking problem. The key question to ask yourself:
Why does starting each recursive call from start+1 (not 1) prevent duplicate combinations?
Answering that is where it clicks, and it's exactly what the guided walkthrough below builds with you: the pattern reasoning, a progressive hint ladder that never spoils the answer, a row-by-row dry run, the optimized solution, and an in-browser editor to run your code against real test cases.
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