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Valid Parentheses

Asked at:GoogleAmazonMeta

Given a string made up of brackets: (, ), {, }, [, ], determine whether all the brackets are correctly matched and properly nested.

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Problem

Given a string s containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.

Input

A string `s` containing only the characters `(`, `)`, `{`, `}`, `[`, `]`.

Output

A boolean. `true` if every opening bracket is closed by the correct type in the right order, `false` otherwise.

Examples

Input: s = "()"

Output: true

Input: s = "()[]{}"

Output: true

Three separate valid pairs, none nested.

Input: s = "(]"

Output: false

The open paren is closed by a bracket, wrong type.

Input: s = "([)]"

Output: false

The brackets are interleaved incorrectly: [ is closed before ( is closed.

The brute-force approach

Repeatedly scan the string and remove any directly-adjacent matched pair (like '()' or '[]'). Keep doing this until either the string is empty (valid) or you can't find any more pairs to remove (invalid).

while '()' in s or '[]' in s or '{}' in s:
    s = s.replace('()', '')    # ← repeated scans and replacements
    s = s.replace('[]', '')
    s = s.replace('{}', '')

return s == ''

Each replacement pass is O(n) and you may need up to O(n) passes in the worst case, giving O(n²) total. The string also gets reallocated on every replacement.

Time: O(n²)Space: O(n)

Spotting the pattern

This is a Stack problem. The key question to ask yourself:

When I hit a closing bracket, how do I know which opener it belongs to?

Answering that is where it clicks, and it's exactly what the guided walkthrough below builds with you: the pattern reasoning, a progressive hint ladder that never spoils the answer, a row-by-row dry run, the optimized solution, and an in-browser editor to run your code against real test cases.

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