Find Peak Element
A peak element is one that is strictly greater than its neighbors. Given an integer array, find any peak element's index. The algorithm must run in O(log n).
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Problem
A peak element is an element that is strictly greater than its neighbors. Given a 0-indexed integer array nums, find a peak element, and return its index. If the array contains multiple peaks, return the index to any of the peaks.
Input
An integer array `nums`. Assume nums[-1] = nums[n] = -infinity.
Output
The index of any peak element.
Examples
Input: nums = [1,2,3,1]
Output: 2
nums[2]=3 is a peak. nums[2] > nums[1] and nums[2] > nums[3].
Input: nums = [1,2,1,3,5,6,4]
Output: 5
nums[5]=6 or nums[1]=2 are both valid peaks.
The brute-force approach
Scan left to right. Return the first index where the element is greater than both neighbors.
for i in range(n):
left_ok = (i == 0 or nums[i] > nums[i-1])
right_ok = (i == n-1 or nums[i] > nums[i+1])
if left_ok and right_ok:
return iO(n) — linear scan.
Spotting the pattern
This is a Binary Search problem. The key question to ask yourself:
If nums[mid] < nums[mid+1], why is it guaranteed that a peak exists somewhere in nums[mid+1..right]?
Answering that is where it clicks, and it's exactly what the guided walkthrough below builds with you: the pattern reasoning, a progressive hint ladder that never spoils the answer, a row-by-row dry run, the optimized solution, and an in-browser editor to run your code against real test cases.
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