Gas Station
There are n gas stations in a circle. You have a car with an unlimited gas tank. At station i you get gas[i] units of gas; traveling to the next station costs cost[i]. Starting at any station, can you complete the full circuit? Return the starting station index, or -1 if it's impossible.
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Problem
There are n gas stations along a circular route. Given two integer arrays gas and cost, return the starting gas station's index if you can travel around the circuit once in the clockwise direction, otherwise return -1.
Input
Two arrays `gas` and `cost`, each of length n.
Output
The index of the starting station, or `-1` if no solution exists.
Examples
Input: gas = [1,2,3,4,5], cost = [3,4,5,1,2]
Output: 3
Start at station 3 (gain 4-1=3), go to 4 (gain 5-2=3+3=6), go to 0 (gain 1-3=4), go to 1 (gain 2-4=2), go to 2 (gain 3-5=0), return to 3. Circuit complete.
Input: gas = [2,3,4], cost = [3,4,3]
Output: -1
The brute-force approach
Try starting at every station. Simulate the trip around the circuit and check if you ever run out of gas.
for start in range(n):
tank = 0
for i in range(n):
station = (start + i) % n
tank += gas[station] - cost[station]
if tank < 0: break
else: return start
return -1O(n²) — simulating from each start takes O(n).
Spotting the pattern
This is a Greedy problem. The key question to ask yourself:
If you're traveling from station s and you run out of gas at station k, why can't any station between s and k be the valid starting station?
Answering that is where it clicks, and it's exactly what the guided walkthrough below builds with you: the pattern reasoning, a progressive hint ladder that never spoils the answer, a row-by-row dry run, the optimized solution, and an in-browser editor to run your code against real test cases.
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