House Robber
You're planning to rob houses along a street. Each house has a certain amount of money, but you cannot rob two adjacent houses (the alarm will trigger). Given the amounts, return the maximum you can steal without triggering any alarm.
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Problem
You are a professional robber planning to rob houses along a street. Adjacent houses have security systems connected — robbing two adjacent houses will alert the police. Given an integer array nums representing the amount of money of each house, return the maximum amount of money you can rob tonight without alerting the police.
Input
An integer array `nums` where `nums[i]` is the amount of money at house i.
Output
An integer, the maximum amount you can rob without robbing two adjacent houses.
Examples
Input: nums = [1, 2, 3, 1]
Output: 4
Rob house 0 (1) + house 2 (3) = 4.
Input: nums = [2, 7, 9, 3, 1]
Output: 12
Rob house 0 (2) + house 2 (9) + house 4 (1) = 12.
The brute-force approach
Try every possible subset of houses. For each subset, check that no two selected houses are adjacent. Track the maximum total among all valid subsets.
max_loot = 0
for each subset of houses:
if no two houses in subset are adjacent:
max_loot = max(max_loot, sum of subset)
return max_lootThere are 2^n possible subsets to check, exponential. And many subsets share the same structure. If you know the best outcome through house i−1, you can compute house i's best outcome directly without re-examining all prior houses.
Spotting the pattern
This is a Dynamic Programming problem. The key question to ask yourself:
At each house, which is better: robbing it (plus the best from two houses back), or skipping it (keeping the best from one house back)?
Answering that is where it clicks, and it's exactly what the guided walkthrough below builds with you: the pattern reasoning, a progressive hint ladder that never spoils the answer, a row-by-row dry run, the optimized solution, and an in-browser editor to run your code against real test cases.
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