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PremiumTwo HeapsHard

IPO

Asked at:Amazon

You can complete at most k projects before an IPO. Each project has a profit and a capital requirement. Starting with initial capital w, pick at most k projects to maximize your final capital. You can only start a project if your current capital meets its requirement.

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Problem

LeetCode will start its IPO soon. To maximize its total capital, it can finish at most k distinct projects before the IPO. Each project has a pure profit and a minimum capital required. Given k, w (initial capital), and two arrays profits and capital, return the maximized total capital after finishing at most k distinct projects.

Input

Integers k (max projects) and w (starting capital), plus arrays `profits` and `capital` where project i has profit profits[i] and requires capital[i] to start.

Output

The maximum capital you can accumulate after completing at most k projects.

Examples

Input: k = 2, w = 0, profits = [1,2,3], capital = [0,1,1]

Output: 4

Start with w=0. Only project 0 is affordable (capital=0). Complete it: w=1. Now projects 1 and 2 are affordable. Pick project 2 (profit=3): w=4. Done after 2 projects.

Input: k = 3, w = 0, profits = [1,2,3], capital = [0,1,2]

Output: 6

Complete all three in order. Each completion unlocks the next.

The brute-force approach

At each step, scan all unfinished projects, filter to those you can afford, pick the one with the highest profit, add its profit to w. Repeat up to k times.

for _ in range(k):
    best = max((p for c,p in zip(capital,profits) if c <= w and not done),
               default=None)
    if best is None: break
    w += best
    mark best as done

O(k × n) — each of the k rounds scans all n projects.

Time: O(k × n)Space: O(n)

Spotting the pattern

This is a Two Heaps problem. The key question to ask yourself:

At each step, which projects become available, and among those, which should you always pick?

Answering that is where it clicks, and it's exactly what the guided walkthrough below builds with you: the pattern reasoning, a progressive hint ladder that never spoils the answer, a row-by-row dry run, the optimized solution, and an in-browser editor to run your code against real test cases.

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