Merge K Sorted Lists
Given an array of k linked lists, each sorted in ascending order, merge them all into one sorted linked list and return it.
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Problem
You are given an array of k linked-lists lists, each linked-list is sorted in ascending order. Merge all the linked-lists into one sorted linked-list and return it.
Input
An array of k linked list heads.
Output
The head of the single merged sorted linked list.
Examples
Input: lists = [[1,4,5],[1,3,4],[2,6]]
Output: [1,1,2,3,4,4,5,6]
Input: lists = []
Output: []
The brute-force approach
Collect all node values into an array, sort it, then build a new linked list from the sorted values.
vals = []
for each list in lists:
while head: vals.append(head.val); head = head.next
vals.sort()
dummy = ListNode(0)
curr = dummy
for v in vals:
curr.next = ListNode(v)
curr = curr.next
return dummy.nextO(N log N) where N is total nodes — sorting all values together. Also uses O(N) extra space for the values array.
Spotting the pattern
This is a K-Way Merge problem. The key question to ask yourself:
At any moment, you have one candidate from each of the k lists. Which data structure finds the minimum among k candidates in O(log k)?
Answering that is where it clicks, and it's exactly what the guided walkthrough below builds with you: the pattern reasoning, a progressive hint ladder that never spoils the answer, a row-by-row dry run, the optimized solution, and an in-browser editor to run your code against real test cases.
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