Minimum Path Sum
Given an m x n grid of non-negative integers, find the path from top-left to bottom-right that minimizes the sum of all numbers along the path. You can only move right or down.
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Problem
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right, which minimizes the sum of all numbers along its path. You can only move either down or right at any point in time.
Input
An m x n integer grid `grid`.
Output
The minimum sum path from grid[0][0] to grid[m-1][n-1].
Examples
Input: grid = [[1,3,1],[1,5,1],[4,2,1]]
Output: 7
Path: 1→3→1→1→1 = 7.
Input: grid = [[1,2,3],[4,5,6]]
Output: 12
The brute-force approach
Recursively try all paths (right and down). Return the minimum sum path from (0,0) to (m-1,n-1).
def min_path(r, c):
if r == m-1 and c == n-1: return grid[r][c]
if r == m-1: return grid[r][c] + min_path(r, c+1)
if c == n-1: return grid[r][c] + min_path(r+1, c)
return grid[r][c] + min(min_path(r+1,c), min_path(r,c+1))O(2^(m+n)) — exponential without memoization.
Spotting the pattern
This is a Dynamic Programming problem. The key question to ask yourself:
At cell (i,j), you can arrive from above (i-1,j) or from the left (i,j-1). Why do you take the minimum of those two, not the maximum?
Answering that is where it clicks, and it's exactly what the guided walkthrough below builds with you: the pattern reasoning, a progressive hint ladder that never spoils the answer, a row-by-row dry run, the optimized solution, and an in-browser editor to run your code against real test cases.
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