Minimum Window Substring
Given strings s and t, return the minimum window in s that contains all characters of t (including duplicates). If no window exists, return an empty string.
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Problem
Given two strings s and t of lengths m and n respectively, return the minimum window substring of s such that every character in t (including duplicates) is included in the window. If there is no such substring, return the empty string.
Input
A string `s` and a string `t`.
Output
The minimum length substring of `s` that contains every character of `t`. Return `""` if none exists.
Examples
Input: s = "ADOBECODEBANC", t = "ABC"
Output: "BANC"
"BANC" is the shortest window containing A, B, and C.
Input: s = "a", t = "a"
Output: "a"
Input: s = "a", t = "aa"
Output: ""
t needs two 'a's but s only has one.
The brute-force approach
Try every substring of s. For each, check if it contains all characters of t. Track the shortest valid one.
best = ""
for i in range(len(s)):
for j in range(i+1, len(s)+1):
if has_all(s[i:j], t):
if not best or j-i < len(best):
best = s[i:j]
return bestO(n²×|t|) — all substrings plus a check per substring.
Spotting the pattern
This is a Sliding Window problem. The key question to ask yourself:
How does the "formed" counter let you know exactly when the window is valid without re-scanning the entire window each time the right pointer moves?
Answering that is where it clicks, and it's exactly what the guided walkthrough below builds with you: the pattern reasoning, a progressive hint ladder that never spoils the answer, a row-by-row dry run, the optimized solution, and an in-browser editor to run your code against real test cases.
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