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Minimum Window Substring

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Given strings s and t, return the minimum window in s that contains all characters of t (including duplicates). If no window exists, return an empty string.

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Problem

Given two strings s and t of lengths m and n respectively, return the minimum window substring of s such that every character in t (including duplicates) is included in the window. If there is no such substring, return the empty string.

Input

A string `s` and a string `t`.

Output

The minimum length substring of `s` that contains every character of `t`. Return `""` if none exists.

Examples

Input: s = "ADOBECODEBANC", t = "ABC"

Output: "BANC"

"BANC" is the shortest window containing A, B, and C.

Input: s = "a", t = "a"

Output: "a"

Input: s = "a", t = "aa"

Output: ""

t needs two 'a's but s only has one.

The brute-force approach

Try every substring of s. For each, check if it contains all characters of t. Track the shortest valid one.

best = ""
for i in range(len(s)):
    for j in range(i+1, len(s)+1):
        if has_all(s[i:j], t):
            if not best or j-i < len(best):
                best = s[i:j]
return best

O(n²×|t|) — all substrings plus a check per substring.

Time: O(n²×|t|)Space: O(|t|)

Spotting the pattern

This is a Sliding Window problem. The key question to ask yourself:

How does the "formed" counter let you know exactly when the window is valid without re-scanning the entire window each time the right pointer moves?

Answering that is where it clicks, and it's exactly what the guided walkthrough below builds with you: the pattern reasoning, a progressive hint ladder that never spoils the answer, a row-by-row dry run, the optimized solution, and an in-browser editor to run your code against real test cases.

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