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Valid Sudoku

Asked at:AmazonGoogleApple

Determine if a 9×9 Sudoku board is valid. Only filled cells need to be validated. Each row, column, and 3×3 box must contain digits 1-9 with no repetition.

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Problem

Determine if a 9 x 9 Sudoku board is valid according to the following rules: each row, column, and 3x3 sub-box must contain the digits 1-9 without repetition.

Input

A 9×9 character grid `board` where empty cells are `'.'`.

Output

`true` if the board is valid, `false` otherwise.

Examples

Input: board = [["5","3",".",".","7",".",".",".","."],["6",".",".","1","9","5",".",".","."],[".","9","8",".",".",".",".","6","."],["8",".",".",".","6",".",".",".","3"],["4",".",".","8",".","3",".",".","1"],["7",".",".",".","2",".",".",".","6"],[".","6",".",".",".",".","2","8","."],[".",".",".","4","1","9",".",".","5"],[".",".",".",".","8",".",".","7","9"]]

Output: true

The brute-force approach

For each row, column, and 3×3 box, collect non-empty values into an array and check for duplicates by sorting or using a set.

for each row in board:
    check no duplicates among non-'.' values
for each col index in 0..8:
    check no duplicates in that column
for each box (row/3, col/3) in 0..2 × 0..2:
    check no duplicates in that box

This is already O(81) = O(1) since the board is fixed size. The question is about clean implementation.

Time: O(81) = O(1)Space: O(81) = O(1)

Spotting the pattern

This is a Set problem. The key question to ask yourself:

For a cell at row r and column c, which 3×3 box does it belong to? How do you compute a unique index for that box?

Answering that is where it clicks, and it's exactly what the guided walkthrough below builds with you: the pattern reasoning, a progressive hint ladder that never spoils the answer, a row-by-row dry run, the optimized solution, and an in-browser editor to run your code against real test cases.

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